Base | Representation |
---|---|
bin | 1011001100101101100100… |
… | …1011101111001111101111 |
3 | 1121121010001112102211101102 |
4 | 2303023121023233033233 |
5 | 3103214031110101221 |
6 | 42104305011033315 |
7 | 2410405054104236 |
oct | 263133113571757 |
9 | 47533045384342 |
10 | 12313020003311 |
11 | 3a17a16879315 |
12 | 146a41959b83b |
13 | 6b4160aa4c61 |
14 | 307d4bdb5b1d |
15 | 16545368330b |
hex | b32d92ef3ef |
12313020003311 has 2 divisors, whose sum is σ = 12313020003312. Its totient is φ = 12313020003310.
The previous prime is 12313020003293. The next prime is 12313020003313. The reversal of 12313020003311 is 11330002031321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12313020003311 - 210 = 12313020002287 is a prime.
It is a super-2 number, since 2×123130200033112 (a number of 27 digits) contains 22 as substring.
Together with 12313020003313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313020003313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156510001655 + 6156510001656.
It is an arithmetic number, because the mean of its divisors is an integer number (6156510001656).
Almost surely, 212313020003311 is an apocalyptic number.
12313020003311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313020003311 is an equidigital number, since it uses as much as digits as its factorization.
12313020003311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12313020003311 its reverse (11330002031321), we get a palindrome (23643022034632).
The spelling of 12313020003311 in words is "twelve trillion, three hundred thirteen billion, twenty million, three thousand, three hundred eleven".
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