Base | Representation |
---|---|
bin | 10110111011110101… |
… | …10101010111011111 |
3 | 1011210010022102100121 |
4 | 23131322311113133 |
5 | 200204124403041 |
6 | 5353452535411 |
7 | 614062545442 |
oct | 133572652737 |
9 | 34703272317 |
10 | 12313122271 |
11 | 524948900a |
12 | 2477781567 |
13 | 1212ca8388 |
14 | 84b449659 |
15 | 4c0ec27d1 |
hex | 2ddeb55df |
12313122271 has 2 divisors, whose sum is σ = 12313122272. Its totient is φ = 12313122270.
The previous prime is 12313122193. The next prime is 12313122277. The reversal of 12313122271 is 17222131321.
It is a strong prime.
It is an emirp because it is prime and its reverse (17222131321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12313122271 - 29 = 12313121759 is a prime.
It is a super-2 number, since 2×123131222712 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313122277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156561135 + 6156561136.
It is an arithmetic number, because the mean of its divisors is an integer number (6156561136).
Almost surely, 212313122271 is an apocalyptic number.
12313122271 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313122271 is an equidigital number, since it uses as much as digits as its factorization.
12313122271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1008, while the sum is 25.
Adding to 12313122271 its reverse (17222131321), we get a palindrome (29535253592).
The spelling of 12313122271 in words is "twelve billion, three hundred thirteen million, one hundred twenty-two thousand, two hundred seventy-one".
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