Base | Representation |
---|---|
bin | 10110111011110101… |
… | …10110000100011111 |
3 | 1011210010022120022021 |
4 | 23131322312010133 |
5 | 200204130001101 |
6 | 5353453001011 |
7 | 614062560025 |
oct | 133572660437 |
9 | 34703276267 |
10 | 12313125151 |
11 | 5249490198 |
12 | 2477783167 |
13 | 1212ca9792 |
14 | 84b44a715 |
15 | 4c0ec35a1 |
hex | 2ddeb611f |
12313125151 has 2 divisors, whose sum is σ = 12313125152. Its totient is φ = 12313125150.
The previous prime is 12313125137. The next prime is 12313125217. The reversal of 12313125151 is 15152131321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12313125151 - 27 = 12313125023 is a prime.
It is a super-2 number, since 2×123131251512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12313125101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6156562575 + 6156562576.
It is an arithmetic number, because the mean of its divisors is an integer number (6156562576).
Almost surely, 212313125151 is an apocalyptic number.
12313125151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12313125151 is an equidigital number, since it uses as much as digits as its factorization.
12313125151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 900, while the sum is 25.
Adding to 12313125151 its reverse (15152131321), we get a palindrome (27465256472).
The spelling of 12313125151 in words is "twelve billion, three hundred thirteen million, one hundred twenty-five thousand, one hundred fifty-one".
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