Base | Representation |
---|---|
bin | 10001111010110001110… |
… | …100101001010010111001 |
3 | 11100201022111000000200011 |
4 | 101322301310221102321 |
5 | 130133243031431041 |
6 | 2341401023341521 |
7 | 154650565300405 |
oct | 21726164512271 |
9 | 4321274000604 |
10 | 1231344014521 |
11 | 435234660125 |
12 | 17a7867518a1 |
13 | 8c16625896a |
14 | 43851270105 |
15 | 2206b7eae81 |
hex | 11eb1d294b9 |
1231344014521 has 2 divisors, whose sum is σ = 1231344014522. Its totient is φ = 1231344014520.
The previous prime is 1231344014477. The next prime is 1231344014533. The reversal of 1231344014521 is 1254104431321.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1185659654400 + 45684360121 = 1088880^2 + 213739^2 .
It is a cyclic number.
It is not a de Polignac number, because 1231344014521 - 211 = 1231344012473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1231344014581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615672007260 + 615672007261.
It is an arithmetic number, because the mean of its divisors is an integer number (615672007261).
Almost surely, 21231344014521 is an apocalyptic number.
It is an amenable number.
1231344014521 is a deficient number, since it is larger than the sum of its proper divisors (1).
1231344014521 is an equidigital number, since it uses as much as digits as its factorization.
1231344014521 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1231344014521 its reverse (1254104431321), we get a palindrome (2485448445842).
The spelling of 1231344014521 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, fourteen thousand, five hundred twenty-one".
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