1231344014581 has 2 divisors, whose sum is σ = 1231344014582. Its totient is φ = 1231344014580.

The previous prime is 1231344014533. The next prime is 1231344014617. The reversal of 1231344014581 is 1854104431321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1044400197681 + 186943816900 = 1021959^2 + 432370^2 .

It is a cyclic number.

It is not a de Polignac number, because 1231344014581 - 2²³ = 1231335625973 is a prime.

It is a super-2 number, since 2×1231344014581² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1231344014581.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1231344014521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615672007290 + 615672007291.

It is an arithmetic number, because the mean of its divisors is an integer number (615672007291).

Almost surely, 2^{1231344014581} is an apocalyptic number.

It is an amenable number.

1231344014581 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231344014581 is an equidigital number, since it uses as much as digits as its factorization.

1231344014581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46080, while the sum is 37.

The spelling of 1231344014581 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, fourteen thousand, five hundred eighty-one".