1231344040139 has 2 divisors, whose sum is σ = 1231344040140. Its totient is φ = 1231344040138.

The previous prime is 1231344040133. The next prime is 1231344040141. The reversal of 1231344040139 is 9310404431321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1231344040139 - 2⁴ = 1231344040123 is a prime.

Together with 1231344040141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1231344040099 and 1231344040108.

It is not a weakly prime, because it can be changed into another prime (1231344040133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615672020069 + 615672020070.

It is an arithmetic number, because the mean of its divisors is an integer number (615672020070).

Almost surely, 2^{1231344040139} is an apocalyptic number.

1231344040139 is a deficient number, since it is larger than the sum of its proper divisors (1).

1231344040139 is an equidigital number, since it uses as much as digits as its factorization.

1231344040139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 1231344040139 in words is "one trillion, two hundred thirty-one billion, three hundred forty-four million, forty thousand, one hundred thirty-nine".