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12321314431 is a prime number
BaseRepresentation
bin10110111100110100…
…00101011001111111
31011210200201121212221
423132122011121333
5200213224030211
65354344310211
7614222305336
oct133632053177
934720647787
1012321314431
115253073998
12247a472367
1312148b60ca
1484c57cd1d
154c1a8ec71
hex2de68567f

12321314431 has 2 divisors, whose sum is σ = 12321314432. Its totient is φ = 12321314430.

The previous prime is 12321314387. The next prime is 12321314441. The reversal of 12321314431 is 13441312321.

It is a strong prime.

It is an emirp because it is prime and its reverse (13441312321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12321314431 - 29 = 12321313919 is a prime.

It is a super-2 number, since 2×123213144312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12321314396 and 12321314405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12321314441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6160657215 + 6160657216.

It is an arithmetic number, because the mean of its divisors is an integer number (6160657216).

Almost surely, 212321314431 is an apocalyptic number.

12321314431 is a deficient number, since it is larger than the sum of its proper divisors (1).

12321314431 is an equidigital number, since it uses as much as digits as its factorization.

12321314431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 25.

Adding to 12321314431 its reverse (13441312321), we get a palindrome (25762626752).

The spelling of 12321314431 in words is "twelve billion, three hundred twenty-one million, three hundred fourteen thousand, four hundred thirty-one".