1232214140117 has 2 divisors, whose sum is σ = 1232214140118. Its totient is φ = 1232214140116.

The previous prime is 1232214140089. The next prime is 1232214140119. The reversal of 1232214140117 is 7110414122321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 665519850436 + 566694289681 = 815794^2 + 752791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1232214140117 is a prime.

Together with 1232214140119, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1232214140117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1232214140119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616107070058 + 616107070059.

It is an arithmetic number, because the mean of its divisors is an integer number (616107070059).

Almost surely, 2^{1232214140117} is an apocalyptic number.

It is an amenable number.

1232214140117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1232214140117 is an equidigital number, since it uses as much as digits as its factorization.

1232214140117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 1232214140117 its reverse (7110414122321), we get a palindrome (8342628262438).

The spelling of 1232214140117 in words is "one trillion, two hundred thirty-two billion, two hundred fourteen million, one hundred forty thousand, one hundred seventeen".