Base | Representation |
---|---|
bin | 1011001101010110100001… |
… | …0111010100011001010111 |
3 | 1121122011102121000222122021 |
4 | 2303111220113110121113 |
5 | 3103404034100144133 |
6 | 42113323434114011 |
7 | 2411244336365542 |
oct | 263255027243127 |
9 | 47564377028567 |
10 | 12324012115543 |
11 | 3a21647609997 |
12 | 147058687b907 |
13 | 6b51c319a28b |
14 | 3086b1bd1859 |
15 | 1658986b552d |
hex | b35685d4657 |
12324012115543 has 2 divisors, whose sum is σ = 12324012115544. Its totient is φ = 12324012115542.
The previous prime is 12324012115529. The next prime is 12324012115589. The reversal of 12324012115543 is 34551121042321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12324012115543 - 233 = 12315422180951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12324012115499 and 12324012115508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12324012115243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6162006057771 + 6162006057772.
It is an arithmetic number, because the mean of its divisors is an integer number (6162006057772).
Almost surely, 212324012115543 is an apocalyptic number.
12324012115543 is a deficient number, since it is larger than the sum of its proper divisors (1).
12324012115543 is an equidigital number, since it uses as much as digits as its factorization.
12324012115543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 12324012115543 its reverse (34551121042321), we get a palindrome (46875133157864).
The spelling of 12324012115543 in words is "twelve trillion, three hundred twenty-four billion, twelve million, one hundred fifteen thousand, five hundred forty-three".
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