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123252520130119 is a prime number
BaseRepresentation
bin11100000001100011110110…
…101011100001011001000111
3121011101211022001020001010101
4130001203312223201121013
5112123332130123130434
61114045232011104531
734650462230140162
oct3401436653413107
9534354261201111
10123252520130119
11362aa1114771a6
12119a71b7742147
1353a08801755c3
14226164d348ad9
15e3b133068b14
hex7018f6ae1647

123252520130119 has 2 divisors, whose sum is σ = 123252520130120. Its totient is φ = 123252520130118.

The previous prime is 123252520130101. The next prime is 123252520130137. The reversal of 123252520130119 is 911031025252321.

It is a balanced prime because it is at equal distance from previous prime (123252520130101) and next prime (123252520130137).

It is a cyclic number.

It is not a de Polignac number, because 123252520130119 - 235 = 123218160391751 is a prime.

It is a super-2 number, since 2×1232525201301192 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123252520130149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61626260065059 + 61626260065060.

It is an arithmetic number, because the mean of its divisors is an integer number (61626260065060).

Almost surely, 2123252520130119 is an apocalyptic number.

123252520130119 is a deficient number, since it is larger than the sum of its proper divisors (1).

123252520130119 is an equidigital number, since it uses as much as digits as its factorization.

123252520130119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 37.

The spelling of 123252520130119 in words is "one hundred twenty-three trillion, two hundred fifty-two billion, five hundred twenty million, one hundred thirty thousand, one hundred nineteen".