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12326346530501 is a prime number
BaseRepresentation
bin1011001101011111001110…
…0000011001111011000101
31121122101110021122112221112
42303113303200121323011
53103423324202434001
642114351224454405
72411356233524213
oct263276340317305
947571407575845
1012326346530501
113a226352a6453
121470b1861a405
136b54a5a01ac3
14308853c5bcb3
151659835d3cbb
hexb35f3819ec5

12326346530501 has 2 divisors, whose sum is σ = 12326346530502. Its totient is φ = 12326346530500.

The previous prime is 12326346530413. The next prime is 12326346530503. The reversal of 12326346530501 is 10503564362321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10737614848900 + 1588731681601 = 3276830^2 + 1260449^2 .

It is a cyclic number.

It is not a de Polignac number, because 12326346530501 - 210 = 12326346529477 is a prime.

It is a super-2 number, since 2×123263465305012 (a number of 27 digits) contains 22 as substring.

Together with 12326346530503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12326346530503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6163173265250 + 6163173265251.

It is an arithmetic number, because the mean of its divisors is an integer number (6163173265251).

Almost surely, 212326346530501 is an apocalyptic number.

It is an amenable number.

12326346530501 is a deficient number, since it is larger than the sum of its proper divisors (1).

12326346530501 is an equidigital number, since it uses as much as digits as its factorization.

12326346530501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 41.

The spelling of 12326346530501 in words is "twelve trillion, three hundred twenty-six billion, three hundred forty-six million, five hundred thirty thousand, five hundred one".