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12330042255133 is a prime number
BaseRepresentation
bin1011001101101100111111…
…0010011110011100011101
31121122201222211210211001121
42303123033302132130131
53104003411304131013
642120202045010541
72411546640623461
oct263331762363435
947581884724047
1012330042255133
113a24161456029
12147178a253a51
136b5944589705
14308ac4a084a1
15165aecca358d
hexb36cfc9e71d

12330042255133 has 2 divisors, whose sum is σ = 12330042255134. Its totient is φ = 12330042255132.

The previous prime is 12330042255107. The next prime is 12330042255187. The reversal of 12330042255133 is 33155224003321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12116337607609 + 213704647524 = 3480853^2 + 462282^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12330042255133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12330042255103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165021127566 + 6165021127567.

It is an arithmetic number, because the mean of its divisors is an integer number (6165021127567).

Almost surely, 212330042255133 is an apocalyptic number.

It is an amenable number.

12330042255133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12330042255133 is an equidigital number, since it uses as much as digits as its factorization.

12330042255133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 12330042255133 its reverse (33155224003321), we get a palindrome (45485266258454).

The spelling of 12330042255133 in words is "twelve trillion, three hundred thirty billion, forty-two million, two hundred fifty-five thousand, one hundred thirty-three".