Base | Representation |
---|---|
bin | 10001111100010101010… |
… | …100000101110001100111 |
3 | 11100212121210212112110111 |
4 | 101330111110011301213 |
5 | 130200202334431043 |
6 | 2342234412033451 |
7 | 155040134201311 |
oct | 21742524056147 |
9 | 4325553775414 |
10 | 1233013202023 |
11 | 435a10898429 |
12 | 17ab71762887 |
13 | 8c371007485 |
14 | 4396cc147b1 |
15 | 2211811509d |
hex | 11f15505c67 |
1233013202023 has 2 divisors, whose sum is σ = 1233013202024. Its totient is φ = 1233013202022.
The previous prime is 1233013202021. The next prime is 1233013202059. The reversal of 1233013202023 is 3202023103321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1233013202023 - 21 = 1233013202021 is a prime.
It is a super-2 number, since 2×12330132020232 (a number of 25 digits) contains 22 as substring.
Together with 1233013202021, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1233013201985 and 1233013202003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1233013202021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616506601011 + 616506601012.
It is an arithmetic number, because the mean of its divisors is an integer number (616506601012).
Almost surely, 21233013202023 is an apocalyptic number.
1233013202023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1233013202023 is an equidigital number, since it uses as much as digits as its factorization.
1233013202023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 1233013202023 its reverse (3202023103321), we get a palindrome (4435036305344).
The spelling of 1233013202023 in words is "one trillion, two hundred thirty-three billion, thirteen million, two hundred two thousand, twenty-three".
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