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12330231831341 is a prime number
BaseRepresentation
bin1011001101101101101100…
…0101101001101100101101
31121122202111001112021201122
42303123123011221230231
53104004303322100331
642120232540150325
72411554432165004
oct263333305515455
947582431467648
1012330231831341
113a24249469486
1214718218383a5
136b5974934298
14308b01c75c3b
15165b0e74e17b
hexb36db169b2d

12330231831341 has 2 divisors, whose sum is σ = 12330231831342. Its totient is φ = 12330231831340.

The previous prime is 12330231831319. The next prime is 12330231831343. The reversal of 12330231831341 is 14313813203321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7099080648100 + 5231151183241 = 2664410^2 + 2287171^2 .

It is a cyclic number.

It is not a de Polignac number, because 12330231831341 - 218 = 12330231569197 is a prime.

It is a super-2 number, since 2×123302318313412 (a number of 27 digits) contains 22 as substring.

Together with 12330231831343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12330231831343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165115915670 + 6165115915671.

It is an arithmetic number, because the mean of its divisors is an integer number (6165115915671).

Almost surely, 212330231831341 is an apocalyptic number.

It is an amenable number.

12330231831341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12330231831341 is an equidigital number, since it uses as much as digits as its factorization.

12330231831341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 12330231831341 in words is "twelve trillion, three hundred thirty billion, two hundred thirty-one million, eight hundred thirty-one thousand, three hundred forty-one".