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1233035551141 is a prime number
BaseRepresentation
bin10001111100010110101…
…001010110000110100101
311100212200100220222200121
4101330112221112012211
5130200224100114031
62342240531041541
7155040525153142
oct21742651260645
94325610828617
101233035551141
11435a22472679
1217ab791402b1
138c375830bc4
1443971b913c9
152211a07c011
hex11f16a561a5

1233035551141 has 2 divisors, whose sum is σ = 1233035551142. Its totient is φ = 1233035551140.

The previous prime is 1233035551117. The next prime is 1233035551147. The reversal of 1233035551141 is 1411555303321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 980357416900 + 252678134241 = 990130^2 + 502671^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1233035551141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1233035551097 and 1233035551106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1233035551147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 616517775570 + 616517775571.

It is an arithmetic number, because the mean of its divisors is an integer number (616517775571).

Almost surely, 21233035551141 is an apocalyptic number.

It is an amenable number.

1233035551141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1233035551141 is an equidigital number, since it uses as much as digits as its factorization.

1233035551141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 1233035551141 in words is "one trillion, two hundred thirty-three billion, thirty-five million, five hundred fifty-one thousand, one hundred forty-one".