Base | Representation |
---|---|
bin | 11100000010011001011001… |
… | …100010010011011101101000 |
3 | 121011121022200211122021112011 |
4 | 130002121121202103131220 |
5 | 112130302401341424000 |
6 | 1114131501003525304 |
7 | 34654566036352006 |
oct | 3402313142233550 |
9 | 534538624567464 |
10 | 123310013233000 |
11 | 3632153486a360 |
12 | 119b6381b29834 |
13 | 53a6113429bc9 |
14 | 2264344cb3a76 |
15 | e3c89a67c2ba |
hex | 702659893768 |
123310013233000 has 128 divisors (see below), whose sum is σ = 314831203315200. Its totient is φ = 44832259872000.
The previous prime is 123310013232961. The next prime is 123310013233019. The reversal of 123310013233000 is 332310013321.
It is a super-2 number, since 2×1233100132330002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 62911786 + ... + 64842214.
It is an arithmetic number, because the mean of its divisors is an integer number (2459618775900).
Almost surely, 2123310013233000 is an apocalyptic number.
123310013233000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123310013233000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (157415601657600).
123310013233000 is an abundant number, since it is smaller than the sum of its proper divisors (191521190082200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123310013233000 is a wasteful number, since it uses less digits than its factorization.
123310013233000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1936268 (or 1936254 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 123310013233000 its reverse (332310013321), we get a palindrome (123642323246321).
The spelling of 123310013233000 in words is "one hundred twenty-three trillion, three hundred ten billion, thirteen million, two hundred thirty-three thousand".
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