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12331113220253 is a prime number
BaseRepresentation
bin1011001101110000111110…
…0111111000100010011101
31121122211202111000111000102
42303130033213320202131
53104013104441022003
642120500223310445
72411615323650662
oct263341747704235
947584674014012
1012331113220253
113a24660a39a73
121471a28a4b425
136b5a85412799
14308b86d49a69
15165b61d01588
hexb370f9f889d

12331113220253 has 2 divisors, whose sum is σ = 12331113220254. Its totient is φ = 12331113220252.

The previous prime is 12331113220211. The next prime is 12331113220267. The reversal of 12331113220253 is 35202231113321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10060841765689 + 2270271454564 = 3171883^2 + 1506742^2 .

It is an emirp because it is prime and its reverse (35202231113321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12331113220253 - 212 = 12331113216157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12331113226253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165556610126 + 6165556610127.

It is an arithmetic number, because the mean of its divisors is an integer number (6165556610127).

Almost surely, 212331113220253 is an apocalyptic number.

It is an amenable number.

12331113220253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12331113220253 is an equidigital number, since it uses as much as digits as its factorization.

12331113220253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 12331113220253 its reverse (35202231113321), we get a palindrome (47533344333574).

The spelling of 12331113220253 in words is "twelve trillion, three hundred thirty-one billion, one hundred thirteen million, two hundred twenty thousand, two hundred fifty-three".