Base | Representation |
---|---|
bin | 10110111110000101… |
… | …01011100010110111 |
3 | 1011211102202021221012 |
4 | 23133002223202313 |
5 | 200223440101112 |
6 | 5355404342435 |
7 | 614411620451 |
oct | 133702534267 |
9 | 34742667835 |
10 | 12331956407 |
11 | 5259082411 |
12 | 2481b44a1b |
13 | 1216b70c34 |
14 | 84db4d2d1 |
15 | 4c2993022 |
hex | 2df0ab8b7 |
12331956407 has 2 divisors, whose sum is σ = 12331956408. Its totient is φ = 12331956406.
The previous prime is 12331956379. The next prime is 12331956409. The reversal of 12331956407 is 70465913321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12331956407 - 216 = 12331890871 is a prime.
Together with 12331956409, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12331956409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165978203 + 6165978204.
It is an arithmetic number, because the mean of its divisors is an integer number (6165978204).
Almost surely, 212331956407 is an apocalyptic number.
12331956407 is a deficient number, since it is larger than the sum of its proper divisors (1).
12331956407 is an equidigital number, since it uses as much as digits as its factorization.
12331956407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 12331956407 in words is "twelve billion, three hundred thirty-one million, nine hundred fifty-six thousand, four hundred seven".
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