12333131214037 has 2 divisors, whose sum is σ = 12333131214038. Its totient is φ = 12333131214036.

The previous prime is 12333131213929. The next prime is 12333131214149. The reversal of 12333131214037 is 73041213133321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11666808380241 + 666322833796 = 3415671^2 + 816286^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12333131214037 is a prime.

It is a super-2 number, since 2×12333131214037² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12333131213993 and 12333131214011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12333131814037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6166565607018 + 6166565607019.

It is an arithmetic number, because the mean of its divisors is an integer number (6166565607019).

Almost surely, 2^{12333131214037} is an apocalyptic number.

It is an amenable number.

12333131214037 is a deficient number, since it is larger than the sum of its proper divisors (1).

12333131214037 is an equidigital number, since it uses as much as digits as its factorization.

12333131214037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 34.

Adding to 12333131214037 its reverse (73041213133321), we get a palindrome (85374344347358).

The spelling of 12333131214037 in words is "twelve trillion, three hundred thirty-three billion, one hundred thirty-one million, two hundred fourteen thousand, thirty-seven".