Base | Representation |
---|---|
bin | 1011001101111000011111… |
… | …1001111010110011011010 |
3 | 1121200000222010020012002010 |
4 | 2303132013321322303122 |
5 | 3104031223042322132 |
6 | 42121432352050350 |
7 | 2412016326424542 |
oct | 263360771726332 |
9 | 47600863205063 |
10 | 12333131214042 |
11 | 3a254a7056631 |
12 | 14722b08339b6 |
13 | 6b601751a052 |
14 | 308cd8d6a322 |
15 | 165c2e06a6cc |
hex | b3787e7acda |
12333131214042 has 32 divisors (see below), whose sum is σ = 24686540605440. Its totient is φ = 4107664773680.
The previous prime is 12333131214037. The next prime is 12333131214149. The reversal of 12333131214042 is 24041213133321.
It is a super-2 number, since 2×123331312140422 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71083417 + ... + 71256707.
It is an arithmetic number, because the mean of its divisors is an integer number (771454393920).
Almost surely, 212333131214042 is an apocalyptic number.
12333131214042 is an abundant number, since it is smaller than the sum of its proper divisors (12353409391398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12333131214042 is a wasteful number, since it uses less digits than its factorization.
12333131214042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182978.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 12333131214042 its reverse (24041213133321), we get a palindrome (36374344347363).
The spelling of 12333131214042 in words is "twelve trillion, three hundred thirty-three billion, one hundred thirty-one million, two hundred fourteen thousand, forty-two".
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