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12340767433 is a prime number
BaseRepresentation
bin10110111111001000…
…10010101011001001
31011212001022221101111
423133210102223021
5200233214024213
65400321250321
7614546535541
oct133744225311
934761287344
1012340767433
115263050255
122484a939a1
131218937567
14850da4321
154c3633a3d
hex2df912ac9

12340767433 has 2 divisors, whose sum is σ = 12340767434. Its totient is φ = 12340767432.

The previous prime is 12340767431. The next prime is 12340767473. The reversal of 12340767433 is 33476704321.

It is an a-pointer prime, because the next prime (12340767473) can be obtained adding 12340767433 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12297035664 + 43731769 = 110892^2 + 6613^2 .

It is a cyclic number.

It is not a de Polignac number, because 12340767433 - 21 = 12340767431 is a prime.

Together with 12340767431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12340767431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6170383716 + 6170383717.

It is an arithmetic number, because the mean of its divisors is an integer number (6170383717).

Almost surely, 212340767433 is an apocalyptic number.

It is an amenable number.

12340767433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12340767433 is an equidigital number, since it uses as much as digits as its factorization.

12340767433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 254016, while the sum is 40.

The spelling of 12340767433 in words is "twelve billion, three hundred forty million, seven hundred sixty-seven thousand, four hundred thirty-three".