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123411033019997 is a prime number
BaseRepresentation
bin11100000011110111011110…
…110010001101011001011101
3121011221222110002012011112122
4130003313132302031121131
5112133431243423114442
61114250125040312325
734665103305362312
oct3403673662153135
9534858402164478
10123411033019997
1136360363903528
1211a11a753126a5
1353b27c22b3cb8
1422691a9552d09
15e4030e1a5dd2
hex703ddec8d65d

123411033019997 has 2 divisors, whose sum is σ = 123411033019998. Its totient is φ = 123411033019996.

The previous prime is 123411033019943. The next prime is 123411033020029. The reversal of 123411033019997 is 799910330114321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99941988415801 + 23469044604196 = 9997099^2 + 4844486^2 .

It is an emirp because it is prime and its reverse (799910330114321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123411033019997 - 226 = 123410965911133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123411033019097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61705516509998 + 61705516509999.

It is an arithmetic number, because the mean of its divisors is an integer number (61705516509999).

Almost surely, 2123411033019997 is an apocalyptic number.

It is an amenable number.

123411033019997 is a deficient number, since it is larger than the sum of its proper divisors (1).

123411033019997 is an equidigital number, since it uses as much as digits as its factorization.

123411033019997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1102248, while the sum is 53.

The spelling of 123411033019997 in words is "one hundred twenty-three trillion, four hundred eleven billion, thirty-three million, nineteen thousand, nine hundred ninety-seven".