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123411130115327 is a prime number
BaseRepresentation
bin11100000011110111100100…
…100100100110010011111111
3121011221222200211220010021222
4130003313210210212103333
5112133431443302142302
61114250142425343555
734665105564566135
oct3403674444462377
9534858624803258
10123411130115327
11363604036a06aa
1211a11aa1937bbb
1353b280944b662
1422691b83c9755
15e40317984da2
hex703de49264ff

123411130115327 has 2 divisors, whose sum is σ = 123411130115328. Its totient is φ = 123411130115326.

The previous prime is 123411130115323. The next prime is 123411130115423. The reversal of 123411130115327 is 723511031114321.

It is a weak prime.

It is an emirp because it is prime and its reverse (723511031114321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123411130115327 - 22 = 123411130115323 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123411130115323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61705565057663 + 61705565057664.

It is an arithmetic number, because the mean of its divisors is an integer number (61705565057664).

Almost surely, 2123411130115327 is an apocalyptic number.

123411130115327 is a deficient number, since it is larger than the sum of its proper divisors (1).

123411130115327 is an equidigital number, since it uses as much as digits as its factorization.

123411130115327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 35.

Adding to 123411130115327 its reverse (723511031114321), we get a palindrome (846922161229648).

The spelling of 123411130115327 in words is "one hundred twenty-three trillion, four hundred eleven billion, one hundred thirty million, one hundred fifteen thousand, three hundred twenty-seven".