Base | Representation |
---|---|
bin | 11100000011110111100100… |
… | …100100100110010101011111 |
3 | 121011221222200211220010102112 |
4 | 130003313210210212111133 |
5 | 112133431443302143143 |
6 | 1114250142425344235 |
7 | 34665105564566333 |
oct | 3403674444462537 |
9 | 534858624803375 |
10 | 123411130115423 |
11 | 363604036a0787 |
12 | 11a11aa193807b |
13 | 53b280944b707 |
14 | 22691b83c97c3 |
15 | e40317984e18 |
hex | 703de492655f |
123411130115423 has 2 divisors, whose sum is σ = 123411130115424. Its totient is φ = 123411130115422.
The previous prime is 123411130115327. The next prime is 123411130115443. The reversal of 123411130115423 is 324511031114321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123411130115423 - 28 = 123411130115167 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 123411130115423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123411130115443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61705565057711 + 61705565057712.
It is an arithmetic number, because the mean of its divisors is an integer number (61705565057712).
Almost surely, 2123411130115423 is an apocalyptic number.
123411130115423 is a deficient number, since it is larger than the sum of its proper divisors (1).
123411130115423 is an equidigital number, since it uses as much as digits as its factorization.
123411130115423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 123411130115423 its reverse (324511031114321), we get a palindrome (447922161229744).
The spelling of 123411130115423 in words is "one hundred twenty-three trillion, four hundred eleven billion, one hundred thirty million, one hundred fifteen thousand, four hundred twenty-three".
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