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123413301320117 is a prime number
BaseRepresentation
bin11100000011111001100101…
…111111000101100110110101
3121011222012022011101202100012
4130003321211333011212311
5112134000420114220432
61114251142110030005
734665213440535224
oct3403714577054665
9534865264352305
10123413301320117
1136361318242a26
1211a123a8aa8305
1353b2a9420a513
1422693428cccbb
15e403e33b4cb2
hex703e65fc59b5

123413301320117 has 2 divisors, whose sum is σ = 123413301320118. Its totient is φ = 123413301320116.

The previous prime is 123413301320093. The next prime is 123413301320131. The reversal of 123413301320117 is 711023103314321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77372272414801 + 46041028905316 = 8796151^2 + 6785354^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123413301320117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123413301329117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61706650660058 + 61706650660059.

It is an arithmetic number, because the mean of its divisors is an integer number (61706650660059).

Almost surely, 2123413301320117 is an apocalyptic number.

It is an amenable number.

123413301320117 is a deficient number, since it is larger than the sum of its proper divisors (1).

123413301320117 is an equidigital number, since it uses as much as digits as its factorization.

123413301320117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 32.

Adding to 123413301320117 its reverse (711023103314321), we get a palindrome (834436404634438).

The spelling of 123413301320117 in words is "one hundred twenty-three trillion, four hundred thirteen billion, three hundred one million, three hundred twenty thousand, one hundred seventeen".