Base | Representation |
---|---|
bin | 10001111101101001001… |
… | …010101001111110101011 |
3 | 11101000020212001001002112 |
4 | 101331221022221332223 |
5 | 130211043010440034 |
6 | 2343030144552535 |
7 | 155120036001032 |
oct | 21755112517653 |
9 | 4330225031075 |
10 | 1234420015019 |
11 | 436572a0a8a4 |
12 | 17b2a492274b |
13 | 8c5365cccb9 |
14 | 43a639bb719 |
15 | 2219b8a37ce |
hex | 11f692a9fab |
1234420015019 has 2 divisors, whose sum is σ = 1234420015020. Its totient is φ = 1234420015018.
The previous prime is 1234420015013. The next prime is 1234420015021. The reversal of 1234420015019 is 9105100244321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1234420015019 - 224 = 1234403237803 is a prime.
It is a super-2 number, since 2×12344200150192 (a number of 25 digits) contains 22 as substring.
Together with 1234420015021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1234420015013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617210007509 + 617210007510.
It is an arithmetic number, because the mean of its divisors is an integer number (617210007510).
Almost surely, 21234420015019 is an apocalyptic number.
1234420015019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234420015019 is an equidigital number, since it uses as much as digits as its factorization.
1234420015019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 1234420015019 in words is "one trillion, two hundred thirty-four billion, four hundred twenty million, fifteen thousand, nineteen".
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