Base | Representation |
---|---|
bin | 10001111101101001001… |
… | …011000110010111110111 |
3 | 11101000020212020221121221 |
4 | 101331221023012113313 |
5 | 130211043023200234 |
6 | 2343030151251211 |
7 | 155120036664064 |
oct | 21755113062767 |
9 | 4330225227557 |
10 | 1234420131319 |
11 | 436572a8a211 |
12 | 17b2a4979b07 |
13 | 8c536640c0b |
14 | 43a63a0bc6b |
15 | 2219b8c7eb4 |
hex | 11f692c65f7 |
1234420131319 has 2 divisors, whose sum is σ = 1234420131320. Its totient is φ = 1234420131318.
The previous prime is 1234420131251. The next prime is 1234420131323. The reversal of 1234420131319 is 9131310244321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1234420131319 - 213 = 1234420123127 is a prime.
It is a super-2 number, since 2×12344201313192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1234420131389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 617210065659 + 617210065660.
It is an arithmetic number, because the mean of its divisors is an integer number (617210065660).
Almost surely, 21234420131319 is an apocalyptic number.
1234420131319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1234420131319 is an equidigital number, since it uses as much as digits as its factorization.
1234420131319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 1234420131319 in words is "one trillion, two hundred thirty-four billion, four hundred twenty million, one hundred thirty-one thousand, three hundred nineteen".
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