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12347108981573 is a prime number
BaseRepresentation
bin1011001110101100100100…
…0010110111101101000101
31121201101001020212100102212
42303223021002313231011
53104243334344402243
642132103352113205
72413022604455432
oct263531102675505
947641036770385
1012347108981573
113a3041a14a223
121474b51995805
136b7434343602
143098634d6b89
1516629b25b318
hexb3ac90b7b45

12347108981573 has 2 divisors, whose sum is σ = 12347108981574. Its totient is φ = 12347108981572.

The previous prime is 12347108981497. The next prime is 12347108981609. The reversal of 12347108981573 is 37518980174321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7266782315809 + 5080326665764 = 2695697^2 + 2253958^2 .

It is a cyclic number.

It is not a de Polignac number, because 12347108981573 - 214 = 12347108965189 is a prime.

It is a super-2 number, since 2×123471089815732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12347108981173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6173554490786 + 6173554490787.

It is an arithmetic number, because the mean of its divisors is an integer number (6173554490787).

Almost surely, 212347108981573 is an apocalyptic number.

It is an amenable number.

12347108981573 is a deficient number, since it is larger than the sum of its proper divisors (1).

12347108981573 is an equidigital number, since it uses as much as digits as its factorization.

12347108981573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10160640, while the sum is 59.

The spelling of 12347108981573 in words is "twelve trillion, three hundred forty-seven billion, one hundred eight million, nine hundred eighty-one thousand, five hundred seventy-three".