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123530432044949 is a prime number
BaseRepresentation
bin11100000101100110101011…
…100001010101111110010101
3121012101101122012112002020222
4130011212223201111332111
5112142410311100414244
61114421032544004125
735006531156345006
oct3405465341257625
9535341565462228
10123530432044949
11363a6a64504156
1211a31037900645
1353c0b3cb20a17
142270c94b3b1ad
15e4349b4e9bee
hex7059ab855f95

123530432044949 has 2 divisors, whose sum is σ = 123530432044950. Its totient is φ = 123530432044948.

The previous prime is 123530432044927. The next prime is 123530432045023. The reversal of 123530432044949 is 949440234035321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75198987910225 + 48331444134724 = 8671735^2 + 6952082^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123530432044949 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 123530432044949.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123530432040949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61765216022474 + 61765216022475.

It is an arithmetic number, because the mean of its divisors is an integer number (61765216022475).

Almost surely, 2123530432044949 is an apocalyptic number.

It is an amenable number.

123530432044949 is a deficient number, since it is larger than the sum of its proper divisors (1).

123530432044949 is an equidigital number, since it uses as much as digits as its factorization.

123530432044949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11197440, while the sum is 53.

The spelling of 123530432044949 in words is "one hundred twenty-three trillion, five hundred thirty billion, four hundred thirty-two million, forty-four thousand, nine hundred forty-nine".