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12353131106413 is a prime number
BaseRepresentation
bin1011001111000010111111…
…1111011101000001101101
31121201221120221112222200121
42303300233333131001231
53104343203030401123
642134541115124541
72413325050622626
oct263605777350155
947657527488617
1012353131106413
113a32a2a5117a9
121476152743751
136b7b83b879a6
14309c75224a4d
151664eecb475d
hexb3c2ffdd06d

12353131106413 has 2 divisors, whose sum is σ = 12353131106414. Its totient is φ = 12353131106412.

The previous prime is 12353131106369. The next prime is 12353131106431. The reversal of 12353131106413 is 31460113135321.

Together with next prime (12353131106431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7178766379684 + 5174364726729 = 2679322^2 + 2274723^2 .

It is a cyclic number.

It is not a de Polignac number, because 12353131106413 - 225 = 12353097551981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12353131106513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6176565553206 + 6176565553207.

It is an arithmetic number, because the mean of its divisors is an integer number (6176565553207).

Almost surely, 212353131106413 is an apocalyptic number.

It is an amenable number.

12353131106413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12353131106413 is an equidigital number, since it uses as much as digits as its factorization.

12353131106413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 34.

The spelling of 12353131106413 in words is "twelve trillion, three hundred fifty-three billion, one hundred thirty-one million, one hundred six thousand, four hundred thirteen".