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123531311064142 = 2419147412065709
BaseRepresentation
bin11100000101100111011111…
…111010100010010001001110
3121012101110220110112212220101
4130011213133322202101032
5112142414111113023032
61114421300104241314
735006562022031122
oct3405473772422116
9535343813485811
10123531311064142
11363a73757062a3
1211a3124217023a
1353c0c4cc7c717
142270d39795582
15e434ed77ede7
hex7059dfea244e

123531311064142 has 8 divisors (see below), whose sum is σ = 185739202794600. Its totient is φ = 61618243465944.

The previous prime is 123531311064097. The next prime is 123531311064149. The reversal of 123531311064142 is 241460113135321.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123531311064149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73706032017 + ... + 73706033692.

It is an arithmetic number, because the mean of its divisors is an integer number (23217400349325).

Almost surely, 2123531311064142 is an apocalyptic number.

123531311064142 is a deficient number, since it is larger than the sum of its proper divisors (62207891730458).

123531311064142 is a wasteful number, since it uses less digits than its factorization.

123531311064142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 147412066130.

The product of its (nonzero) digits is 51840, while the sum is 37.

Adding to 123531311064142 its reverse (241460113135321), we get a palindrome (364991424199463).

The spelling of 123531311064142 in words is "one hundred twenty-three trillion, five hundred thirty-one billion, three hundred eleven million, sixty-four thousand, one hundred forty-two".

Divisors: 1 2 419 838 147412065709 294824131418 61765655532071 123531311064142