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123531311064149 is a prime number
BaseRepresentation
bin11100000101100111011111…
…111010100010010001010101
3121012101110220110112212220122
4130011213133322202101111
5112142414111113023044
61114421300104241325
735006562022031132
oct3405473772422125
9535343813485818
10123531311064149
11363a73757062aa
1211a31242170245
1353c0c4cc7c721
142270d39795589
15e434ed77edee
hex7059dfea2455

123531311064149 has 2 divisors, whose sum is σ = 123531311064150. Its totient is φ = 123531311064148.

The previous prime is 123531311064097. The next prime is 123531311064223. The reversal of 123531311064149 is 941460113135321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115518278731249 + 8013032332900 = 10747943^2 + 2830730^2 .

It is a cyclic number.

It is not a de Polignac number, because 123531311064149 - 220 = 123531310015573 is a prime.

It is a super-4 number, since 4×1235313110641494 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123531511064149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61765655532074 + 61765655532075.

It is an arithmetic number, because the mean of its divisors is an integer number (61765655532075).

Almost surely, 2123531311064149 is an apocalyptic number.

It is an amenable number.

123531311064149 is a deficient number, since it is larger than the sum of its proper divisors (1).

123531311064149 is an equidigital number, since it uses as much as digits as its factorization.

123531311064149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 44.

The spelling of 123531311064149 in words is "one hundred twenty-three trillion, five hundred thirty-one billion, three hundred eleven million, sixty-four thousand, one hundred forty-nine".