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123531511064149 is a prime number
BaseRepresentation
bin11100000101100111101011…
…110101011110011001010101
3121012101111102101212221100001
4130011213223311132121111
5112142420013313023044
61114421332011051301
735006600001015406
oct3405475365363125
9535344371787301
10123531511064149
11363a7468599261
1211a31299140b31
1353c0c82536a16
142270d581779ad
15e435110d92d4
hex7059ebd5e655

123531511064149 has 2 divisors, whose sum is σ = 123531511064150. Its totient is φ = 123531511064148.

The previous prime is 123531511064147. The next prime is 123531511064167. The reversal of 123531511064149 is 941460115135321.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79765440322500 + 43766070741649 = 8931150^2 + 6615593^2 .

It is a cyclic number.

It is not a de Polignac number, because 123531511064149 - 21 = 123531511064147 is a prime.

Together with 123531511064147, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 123531511064099 and 123531511064108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123531511064147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61765755532074 + 61765755532075.

It is an arithmetic number, because the mean of its divisors is an integer number (61765755532075).

Almost surely, 2123531511064149 is an apocalyptic number.

It is an amenable number.

123531511064149 is a deficient number, since it is larger than the sum of its proper divisors (1).

123531511064149 is an equidigital number, since it uses as much as digits as its factorization.

123531511064149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 46.

The spelling of 123531511064149 in words is "one hundred twenty-three trillion, five hundred thirty-one billion, five hundred eleven million, sixty-four thousand, one hundred forty-nine".