Base | Representation |
---|---|
bin | 1011001111010011011101… |
… | …1010001011101111011111 |
3 | 1121202100222221110112012212 |
4 | 2303310313122023233133 |
5 | 3104431230413140221 |
6 | 42140551430351035 |
7 | 2413542423212312 |
oct | 263646732135737 |
9 | 47670887415185 |
10 | 12357550521311 |
11 | 3a34898121606 |
12 | 1476b867bb47b |
13 | 6b84096579a8 |
14 | 30a174154979 |
15 | 1666acc85b5b |
hex | b3d3768bbdf |
12357550521311 has 2 divisors, whose sum is σ = 12357550521312. Its totient is φ = 12357550521310.
The previous prime is 12357550521271. The next prime is 12357550521313. The reversal of 12357550521311 is 11312505575321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12357550521311 - 214 = 12357550504927 is a prime.
Together with 12357550521313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12357550521313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6178775260655 + 6178775260656.
It is an arithmetic number, because the mean of its divisors is an integer number (6178775260656).
Almost surely, 212357550521311 is an apocalyptic number.
12357550521311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12357550521311 is an equidigital number, since it uses as much as digits as its factorization.
12357550521311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 157500, while the sum is 41.
The spelling of 12357550521311 in words is "twelve trillion, three hundred fifty-seven billion, five hundred fifty million, five hundred twenty-one thousand, three hundred eleven".
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