Base | Representation |
---|---|
bin | 11100000111111100010001… |
… | …000000100000001100110111 |
3 | 121012221202012211201111110011 |
4 | 130013330101000200030313 |
5 | 112203023231404031241 |
6 | 1115022514440041051 |
7 | 35024245326612211 |
oct | 3407742100401467 |
9 | 535852184644404 |
10 | 123691048502071 |
11 | 36459096295706 |
12 | 11a581a1a63187 |
13 | 54030289c8b6b |
14 | 227897047d5b1 |
15 | e4774c156281 |
hex | 707f11020337 |
123691048502071 has 2 divisors, whose sum is σ = 123691048502072. Its totient is φ = 123691048502070.
The previous prime is 123691048501997. The next prime is 123691048502081. The reversal of 123691048502071 is 170205840196321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123691048502071 - 213 = 123691048493879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123691048502081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61845524251035 + 61845524251036.
It is an arithmetic number, because the mean of its divisors is an integer number (61845524251036).
It is a 1-persistent number, because it is pandigital, but 2⋅123691048502071 = 247382097004142 is not.
Almost surely, 2123691048502071 is an apocalyptic number.
123691048502071 is a deficient number, since it is larger than the sum of its proper divisors (1).
123691048502071 is an equidigital number, since it uses as much as digits as its factorization.
123691048502071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 49.
Adding to 123691048502071 its reverse (170205840196321), we get a palindrome (293896888698392).
The spelling of 123691048502071 in words is "one hundred twenty-three trillion, six hundred ninety-one billion, forty-eight million, five hundred two thousand, seventy-one".
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