Base | Representation |
---|---|
bin | 1011010000001110011010… |
… | …1011111110100111110011 |
3 | 1121210212211212002021010102 |
4 | 2310003212223332213303 |
5 | 3110211133240211401 |
6 | 42152130035423015 |
7 | 2414642536343213 |
oct | 264034653764763 |
9 | 47725755067112 |
10 | 12373376100851 |
11 | 3a40579265767 |
12 | 147a062754a6b |
13 | 6b9a5c24183c |
14 | 30ac35c82243 |
15 | 166cd72c656b |
hex | b40e6afe9f3 |
12373376100851 has 2 divisors, whose sum is σ = 12373376100852. Its totient is φ = 12373376100850.
The previous prime is 12373376100817. The next prime is 12373376100853. The reversal of 12373376100851 is 15800167337321.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12373376100851 is a prime.
It is a super-2 number, since 2×123733761008512 (a number of 27 digits) contains 22 as substring.
Together with 12373376100853, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12373376100796 and 12373376100805.
It is not a weakly prime, because it can be changed into another prime (12373376100853) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6186688050425 + 6186688050426.
It is an arithmetic number, because the mean of its divisors is an integer number (6186688050426).
Almost surely, 212373376100851 is an apocalyptic number.
12373376100851 is a deficient number, since it is larger than the sum of its proper divisors (1).
12373376100851 is an equidigital number, since it uses as much as digits as its factorization.
12373376100851 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 635040, while the sum is 47.
The spelling of 12373376100851 in words is "twelve trillion, three hundred seventy-three billion, three hundred seventy-six million, one hundred thousand, eight hundred fifty-one".
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