123804943 has 2 divisors, whose sum is σ = 123804944. Its totient is φ = 123804942.

The previous prime is 123804913. The next prime is 123804971. The reversal of 123804943 is 349408321.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 123804943 - 2⁵ = 123804911 is a prime.

It is a super-2 number, since 2×123804943² = 30655327822466498, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123804899 and 123804908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123804913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61902471 + 61902472.

It is an arithmetic number, because the mean of its divisors is an integer number (61902472).

Almost surely, 2^123804943 is an apocalyptic number.

123804943 is a deficient number, since it is larger than the sum of its proper divisors (1).

123804943 is an equidigital number, since it uses as much as digits as its factorization.

123804943 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 34.

The square root of 123804943 is about 11126.7669608022. The cubic root of 123804943 is about 498.4014856163.

The spelling of 123804943 in words is "one hundred twenty-three million, eight hundred four thousand, nine hundred forty-three".