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12395220127 is a prime number
BaseRepresentation
bin10111000101101000…
…00000110010011111
31011222211210102102221
423202310000302133
5200341134021002
65405544330211
7616110430003
oct134264006237
934884712387
1012395220127
115290862384
12249b173967
131226cc15a4
148582da703
154c82dcc37
hex2e2d00c9f

12395220127 has 2 divisors, whose sum is σ = 12395220128. Its totient is φ = 12395220126.

The previous prime is 12395220121. The next prime is 12395220137. The reversal of 12395220127 is 72102259321.

It is a weak prime.

It is an emirp because it is prime and its reverse (72102259321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12395220127 - 211 = 12395218079 is a prime.

It is a super-2 number, since 2×123952201272 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12395220092 and 12395220101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12395220121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6197610063 + 6197610064.

It is an arithmetic number, because the mean of its divisors is an integer number (6197610064).

Almost surely, 212395220127 is an apocalyptic number.

12395220127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12395220127 is an equidigital number, since it uses as much as digits as its factorization.

12395220127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 12395220127 its reverse (72102259321), we get a palindrome (84497479448).

The spelling of 12395220127 in words is "twelve billion, three hundred ninety-five million, two hundred twenty thousand, one hundred twenty-seven".