Base | Representation |
---|---|
bin | 11100001100011101000001… |
… | …101101101111000111101101 |
3 | 121021001101112002112202111121 |
4 | 130030131001231233013231 |
5 | 112223113224421430331 |
6 | 1115421153114420541 |
7 | 35055532636164364 |
oct | 3414350155570755 |
9 | 537041462482447 |
10 | 124001103311341 |
11 | 36568633131a33 |
12 | 11aa82b2731751 |
13 | 542633b995349 |
14 | 2289984b307db |
15 | e508473ecc11 |
hex | 70c741b6f1ed |
124001103311341 has 2 divisors, whose sum is σ = 124001103311342. Its totient is φ = 124001103311340.
The previous prime is 124001103311333. The next prime is 124001103311357. The reversal of 124001103311341 is 143113301100421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 64899603248841 + 59101500062500 = 8056029^2 + 7687750^2 .
It is a cyclic number.
It is not a de Polignac number, because 124001103311341 - 23 = 124001103311333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (124001103311321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62000551655670 + 62000551655671.
It is an arithmetic number, because the mean of its divisors is an integer number (62000551655671).
Almost surely, 2124001103311341 is an apocalyptic number.
It is an amenable number.
124001103311341 is a deficient number, since it is larger than the sum of its proper divisors (1).
124001103311341 is an equidigital number, since it uses as much as digits as its factorization.
124001103311341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 124001103311341 its reverse (143113301100421), we get a palindrome (267114404411762).
The spelling of 124001103311341 in words is "one hundred twenty-four trillion, one billion, one hundred three million, three hundred eleven thousand, three hundred forty-one".
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