1240146133 has 2 divisors, whose sum is σ = 1240146134. Its totient is φ = 1240146132.

The previous prime is 1240146121. The next prime is 1240146143. The reversal of 1240146133 is 3316410421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1233906129 + 6240004 = 35127^2 + 2498^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1240146133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1240146098 and 1240146107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240146113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620073066 + 620073067.

It is an arithmetic number, because the mean of its divisors is an integer number (620073067).

Almost surely, 2^1240146133 is an apocalyptic number.

It is an amenable number.

1240146133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240146133 is an equidigital number, since it uses as much as digits as its factorization.

1240146133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

The square root of 1240146133 is about 35215.7086113569. The cubic root of 1240146133 is about 1074.3792725837.

Adding to 1240146133 its reverse (3316410421), we get a palindrome (4556556554).

The spelling of 1240146133 in words is "one billion, two hundred forty million, one hundred forty-six thousand, one hundred thirty-three".