1240221221431 has 2 divisors, whose sum is σ = 1240221221432. Its totient is φ = 1240221221430.

The previous prime is 1240221221341. The next prime is 1240221221497. The reversal of 1240221221431 is 1341221220421.

Together with previous prime (1240221221341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1240221221431 - 2⁷ = 1240221221303 is a prime.

It is a super-2 number, since 2×1240221221431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1240221221396 and 1240221221405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1240221221531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620110610715 + 620110610716.

It is an arithmetic number, because the mean of its divisors is an integer number (620110610716).

Almost surely, 2^{1240221221431} is an apocalyptic number.

1240221221431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1240221221431 is an equidigital number, since it uses as much as digits as its factorization.

1240221221431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1240221221431 its reverse (1341221220421), we get a palindrome (2581442441852).

The spelling of 1240221221431 in words is "one trillion, two hundred forty billion, two hundred twenty-one million, two hundred twenty-one thousand, four hundred thirty-one".