Base | Representation |
---|---|
bin | 10010000011000100001… |
… | …000011101100101011001 |
3 | 11101120021112111112000121 |
4 | 102003010020131211121 |
5 | 130310003212241123 |
6 | 2345431531433241 |
7 | 155414221461115 |
oct | 22030410354531 |
9 | 4346245445017 |
10 | 1240241133913 |
11 | 438a8a872661 |
12 | 18044a2b5821 |
13 | 8cc535c7252 |
14 | 44056b44745 |
15 | 223dc95475d |
hex | 120c421d959 |
1240241133913 has 2 divisors, whose sum is σ = 1240241133914. Its totient is φ = 1240241133912.
The previous prime is 1240241133847. The next prime is 1240241133947. The reversal of 1240241133913 is 3193311420421.
It is an a-pointer prime, because the next prime (1240241133947) can be obtained adding 1240241133913 to its sum of digits (34).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 869345517769 + 370895616144 = 932387^2 + 609012^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240241133913 - 229 = 1239704263001 is a prime.
It is not a weakly prime, because it can be changed into another prime (1240241133973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620120566956 + 620120566957.
It is an arithmetic number, because the mean of its divisors is an integer number (620120566957).
Almost surely, 21240241133913 is an apocalyptic number.
It is an amenable number.
1240241133913 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240241133913 is an equidigital number, since it uses as much as digits as its factorization.
1240241133913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 1240241133913 in words is "one trillion, two hundred forty billion, two hundred forty-one million, one hundred thirty-three thousand, nine hundred thirteen".
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