12402415031 has 2 divisors, whose sum is σ = 12402415032. Its totient is φ = 12402415030.

The previous prime is 12402415027. The next prime is 12402415033. The reversal of 12402415031 is 13051420421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12402415031 - 2² = 12402415027 is a prime.

It is a super-2 number, since 2×12402415031² (a number of 21 digits) contains 22 as substring.

Together with 12402415033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12402414988 and 12402415006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12402415033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201207515 + 6201207516.

It is an arithmetic number, because the mean of its divisors is an integer number (6201207516).

Almost surely, 2^12402415031 is an apocalyptic number.

12402415031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12402415031 is an equidigital number, since it uses as much as digits as its factorization.

12402415031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 12402415031 its reverse (13051420421), we get a palindrome (25453835452).

The spelling of 12402415031 in words is "twelve billion, four hundred two million, four hundred fifteen thousand, thirty-one".