Base | Representation |
---|---|
bin | 11100001100110010101111… |
… | …000001010101111011001011 |
3 | 121021010121200111222000212111 |
4 | 130030302233001111323023 |
5 | 112224003443433112133 |
6 | 1115440010040523151 |
7 | 35060316355616605 |
oct | 3414625701257313 |
9 | 537117614860774 |
10 | 124024412004043 |
11 | 365775042a2831 |
12 | 11ab09187804b7 |
13 | 54285b49a6ac5 |
14 | 228ab56616175 |
15 | e5125d8871cd |
hex | 70ccaf055ecb |
124024412004043 has 2 divisors, whose sum is σ = 124024412004044. Its totient is φ = 124024412004042.
The previous prime is 124024412004041. The next prime is 124024412004079. The reversal of 124024412004043 is 340400214420421.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 124024412004043 - 21 = 124024412004041 is a prime.
Together with 124024412004041, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 124024412003996 and 124024412004014.
It is not a weakly prime, because it can be changed into another prime (124024412004041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62012206002021 + 62012206002022.
It is an arithmetic number, because the mean of its divisors is an integer number (62012206002022).
Almost surely, 2124024412004043 is an apocalyptic number.
124024412004043 is a deficient number, since it is larger than the sum of its proper divisors (1).
124024412004043 is an equidigital number, since it uses as much as digits as its factorization.
124024412004043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24576, while the sum is 31.
Adding to 124024412004043 its reverse (340400214420421), we get a palindrome (464424626424464).
The spelling of 124024412004043 in words is "one hundred twenty-four trillion, twenty-four billion, four hundred twelve million, four thousand, forty-three".
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