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12402827111 is a prime number
BaseRepresentation
bin10111000110100010…
…00001111101100111
31012000101002220021002
423203101001331213
5200400110431421
65410415343515
7616232201543
oct134321017547
935011086232
1012402827111
115295088644
1224a1821b9b
131228755b6c
1485931aa23
154c8ce1b0b
hex2e3441f67

12402827111 has 2 divisors, whose sum is σ = 12402827112. Its totient is φ = 12402827110.

The previous prime is 12402827053. The next prime is 12402827113. The reversal of 12402827111 is 11172820421.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12402827111 - 210 = 12402826087 is a prime.

Together with 12402827113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12402827113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201413555 + 6201413556.

It is an arithmetic number, because the mean of its divisors is an integer number (6201413556).

Almost surely, 212402827111 is an apocalyptic number.

12402827111 is a deficient number, since it is larger than the sum of its proper divisors (1).

12402827111 is an equidigital number, since it uses as much as digits as its factorization.

12402827111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1792, while the sum is 29.

The spelling of 12402827111 in words is "twelve billion, four hundred two million, eight hundred twenty-seven thousand, one hundred eleven".