12403041001301 has 2 divisors, whose sum is σ = 12403041001302. Its totient is φ = 12403041001300.

The previous prime is 12403041001271. The next prime is 12403041001303. The reversal of 12403041001301 is 10310014030421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11882146808401 + 520894192900 = 3447049^2 + 721730^2 .

It is a cyclic number.

It is not a de Polignac number, because 12403041001301 - 2²² = 12403036806997 is a prime.

Together with 12403041001303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12403041001303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201520500650 + 6201520500651.

It is an arithmetic number, because the mean of its divisors is an integer number (6201520500651).

Almost surely, 2^{12403041001301} is an apocalyptic number.

It is an amenable number.

12403041001301 is a deficient number, since it is larger than the sum of its proper divisors (1).

12403041001301 is an equidigital number, since it uses as much as digits as its factorization.

12403041001301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 12403041001301 its reverse (10310014030421), we get a palindrome (22713055031722).

The spelling of 12403041001301 in words is "twelve trillion, four hundred three billion, forty-one million, one thousand, three hundred one".