Base | Representation |
---|---|
bin | 100100111101101… |
… | …1101011101100101 |
3 | 10012102212222120202 |
4 | 1021323131131211 |
5 | 10020010331231 |
6 | 323024240245 |
7 | 42510402533 |
oct | 11173353545 |
9 | 3172788522 |
10 | 1240323941 |
11 | 58714880a |
12 | 2a7470085 |
13 | 169c725bc |
14 | baa29153 |
15 | 73d535cb |
hex | 49edd765 |
1240323941 has 2 divisors, whose sum is σ = 1240323942. Its totient is φ = 1240323940.
The previous prime is 1240323907. The next prime is 1240323943. The reversal of 1240323941 is 1493230421.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1158040900 + 82283041 = 34030^2 + 9071^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240323941 - 214 = 1240307557 is a prime.
Together with 1240323943, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1240323943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620161970 + 620161971.
It is an arithmetic number, because the mean of its divisors is an integer number (620161971).
Almost surely, 21240323941 is an apocalyptic number.
It is an amenable number.
1240323941 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240323941 is an equidigital number, since it uses as much as digits as its factorization.
1240323941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
The square root of 1240323941 is about 35218.2330760644. The cubic root of 1240323941 is about 1074.4306170974.
The spelling of 1240323941 in words is "one billion, two hundred forty million, three hundred twenty-three thousand, nine hundred forty-one".
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