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1240421252340 = 22351721032512767
BaseRepresentation
bin10010000011001110110…
…111100011110011110100
311101120202002102111001110
4102003032313203303310
5130310340320033330
62345501444155020
7155421536451534
oct22031667436364
94346662374043
101240421252340
11439072506266
1218049a698a70
138cc81a0ccba
1444072a2d4c4
15223ed682db0
hex120cede3cf4

1240421252340 has 288 divisors, whose sum is σ = 3741516140544. Its totient is φ = 306959616000.

The previous prime is 1240421252297. The next prime is 1240421252341. The reversal of 1240421252340 is 432521240421.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1240421252298 and 1240421252307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1240421252341) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 448289637 + ... + 448292403.

It is an arithmetic number, because the mean of its divisors is an integer number (12991375488).

Almost surely, 21240421252340 is an apocalyptic number.

1240421252340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1240421252340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1870758070272).

1240421252340 is an abundant number, since it is smaller than the sum of its proper divisors (2501094888204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1240421252340 is a wasteful number, since it uses less digits than its factorization.

1240421252340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3167 (or 3148 counting only the distinct ones).

The product of its (nonzero) digits is 15360, while the sum is 30.

Adding to 1240421252340 its reverse (432521240421), we get a palindrome (1672942492761).

The spelling of 1240421252340 in words is "one trillion, two hundred forty billion, four hundred twenty-one million, two hundred fifty-two thousand, three hundred forty".