Base | Representation |
---|---|
bin | 10010000011001111100… |
… | …101100010000111000111 |
3 | 11101120202221002202211111 |
4 | 102003033211202013013 |
5 | 130310401411212012 |
6 | 2345502554345451 |
7 | 155422044054562 |
oct | 22031745420707 |
9 | 4346687082744 |
10 | 1240433304007 |
11 | 439079297917 |
12 | 1804a272b287 |
13 | 8cc8436c671 |
14 | 440744894d9 |
15 | 223ee763ba7 |
hex | 120cf9621c7 |
1240433304007 has 2 divisors, whose sum is σ = 1240433304008. Its totient is φ = 1240433304006.
The previous prime is 1240433303999. The next prime is 1240433304013. The reversal of 1240433304007 is 7004033340421.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1240433304007 - 23 = 1240433303999 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1240433304007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1240433302007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620216652003 + 620216652004.
It is an arithmetic number, because the mean of its divisors is an integer number (620216652004).
Almost surely, 21240433304007 is an apocalyptic number.
1240433304007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240433304007 is an equidigital number, since it uses as much as digits as its factorization.
1240433304007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 31.
Adding to 1240433304007 its reverse (7004033340421), we get a palindrome (8244466644428).
The spelling of 1240433304007 in words is "one trillion, two hundred forty billion, four hundred thirty-three million, three hundred four thousand, seven".
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