Base | Representation |
---|---|
bin | 10010000011101101111… |
… | …111100101101101100111 |
3 | 11101122002111000220220221 |
4 | 102003231333211231213 |
5 | 130312423010412413 |
6 | 2350025340505211 |
7 | 155440510202545 |
oct | 22035577455547 |
9 | 4348074026827 |
10 | 1240943450983 |
11 | 439310254895 |
12 | 18060554b207 |
13 | 90035c68192 |
14 | 440c2122d95 |
15 | 2242e43368d |
hex | 120edfe5b67 |
1240943450983 has 2 divisors, whose sum is σ = 1240943450984. Its totient is φ = 1240943450982.
The previous prime is 1240943450977. The next prime is 1240943451017. The reversal of 1240943450983 is 3890543490421.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1240943450983 - 25 = 1240943450951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1240943450983.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1240943450953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620471725491 + 620471725492.
It is an arithmetic number, because the mean of its divisors is an integer number (620471725492).
Almost surely, 21240943450983 is an apocalyptic number.
1240943450983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240943450983 is an equidigital number, since it uses as much as digits as its factorization.
1240943450983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3732480, while the sum is 52.
The spelling of 1240943450983 in words is "one trillion, two hundred forty billion, nine hundred forty-three million, four hundred fifty thousand, nine hundred eighty-three".
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